Java Program - Square Root of a Number
If a number is multiplied by itself (n*n), the final number will be the square of that number and finding the square root of a number is inverse operation of squaring the number. If x is the square root of y, it can be expressed as below:
Alternatively, it can also be expressed as:
x2 = y
Method 1: Using sqrt() method of Java Math Class
The sqrt() method of Java Math class can be used to return square root of a number.
import java.lang.Math; public class MyClass { public static void main(String[] args) { double x = 16; double y = 25; //sqrt() takes double datatype as argument double x1 = Math.sqrt(x); double y1 = Math.sqrt(y); System.out.println("Square root of " + x + " is " + x1); System.out.println("Square root of " + y + " is " + y1); } }
The above code will give the following output:
Square root of 16.0 is 4.0 Square root of 25.0 is 5.0
Method 2: Using pow() method of Java Math Class
The pow() method of Java Math class can also be used to calculate square root of a number.
import java.lang.Math; public class MyClass { public static void main(String[] args) { double x = 16; double y = 25; //pow() takes double datatype as argument double x1 = Math.pow(x, 0.5); double y1 = Math.pow(y, 0.5); System.out.println("Square root of " + x + " is " + x1); System.out.println("Square root of " + y + " is " + y1); } }
The above code will give the following output:
Square root of 16.0 is 4.0 Square root of 25.0 is 5.0
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