Swift - Bitwise OR operator

The Bitwise OR operator (|) is a binary operator which takes two bit patterns of equal length and performs the logical OR operation on each pair of corresponding bits. It returns 1 if either or both bits at the same position are 1, else returns 0.

The example below describes how bitwise OR operator works:

50 | 25 returns 59

     50    ->    110010  (In Binary)
   | 25    ->  | 011001  (In Binary)
    ----        --------
     59    <-    111011  (In Binary)  

The code of using Bitwise OR operator (|) is given below:

var x = 50
var y = 25

//Bitwise OR operation
var z = x | y

//Displaying the result
print("z = \(z)")

The output of the above code will be:

z = 59

Example: Find largest power of 2 less than or equal to given number

Consider an integer 1000. In the bit-wise format, it can be written as 1111101000. However, all bits are not written here. A complete representation will be 32 bit representation as given below:

00000000000000000000001111101000  

Performing n = n | (n>>i) operation, where i = 1, 2, 4, 8, 16 will change all right side bit to 1. When applied on 1000, the result in 32 bit representation is given below:

00000000000000000000001111111111 

Adding one to this result and then right shifting the result by one place will give largest power of 2 less than or equal to 1000.

00000000000000000000001000000000 

The below code will calculate the largest power of 2 less than or equal to given number.

func MaxPowerOfTwo(_ n: Int) -> Int{ 
  var n = n
  //changing all right side bits to 1.
  n = n | (n>>1)
  n = n | (n>>2)
  n = n | (n>>4)
  n = n | (n>>8)
  n = n | (n>>16)
  
  //adding 1 to n makes smallest power
  //of 2 greater than given number
  n = n + 1

  //right shift by one position makes
  //largest power of 2 less than or 
  //equal to given number
  n = n >> 1
  
  return n
}

print("MaxPowerOfTwo(100) = \(MaxPowerOfTwo(100))")
print("MaxPowerOfTwo(500) = \(MaxPowerOfTwo(500))")
print("MaxPowerOfTwo(1000) = \(MaxPowerOfTwo(1000))") 

The above code will give the following output:

MaxPowerOfTwo(100) = 64
MaxPowerOfTwo(500) = 256
MaxPowerOfTwo(1000) = 512