Swift - Bitwise AND operator
The Bitwise AND operator (&) is a binary operator which takes two bit patterns of equal length and performs the logical AND operation on each pair of corresponding bits. It returns 1 if both bits at the same position are 1, else returns 0.
Bit_1 | Bit_2 | Bit_1 & Bit_2 |
---|---|---|
0 | 0 | 0 |
1 | 0 | 0 |
0 | 1 | 0 |
1 | 1 | 1 |
The example below describes how bitwise AND operator works:
50 & 25 returns 16 50 -> 110010 (In Binary) & 25 -> & 011001 (In Binary) ---- -------- 16 <- 010000 (In Binary)
The code of using Bitwise AND operator (&) is given below:
var x = 50 var y = 25 //Bitwise AND operation var z = x & y //Displaying the result print("z = \(z)")
The output of the above code will be:
z = 16
Example: Check if a number is even or odd
The last bit of an even number is always 0, whereas for an odd number the last bit is always 1. Therefore, for a given number n, (n & 1) returns 0 if the n is even, else returns 1.
Even Number: 50 -> 110010 (In Binary) & 1 -> & 000001 (In Binary) ---- -------- 0 <- 000000 Odd Number: 99 -> 1100011 (In Binary) & 1 -> & 0000001 (In Binary) ---- --------- 1 <- 0000001
The below code checks whether a given number is even or odd:
func CheckEven(myNum: Int) { if ((myNum & 1) == 1) { print("\(myNum) is an odd number.") } else { print("\(myNum) is an even number.") } } CheckEven(myNum: 50) CheckEven(myNum: 99)
The above code will give the following output:
50 is an even number. 99 is an odd number.
❮ Swift - Operators