Scala - Math rint() Method

The Scala Math rint() method returns the Double value that is closest to the argument and equal to a mathematical integer. In special cases it returns the following:

If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
If the argument is NaN or an infinity, then the result is the same as the argument.

Syntax

def rint(x: Double): Double = java.lang.Math.rint(x)

Parameters

`x`	Specify a Double value.

Return Value

Returns the Double value that is closest to the argument and equal to a mathematical integer.

Exception

NA.

Example:

In the example below, rint() method returns the Double value that is closest to the given argument and equal to a mathematical integer.

import scala.math._

object MainObject {
  def main(args: Array[String]) {
    println(s"rint(-10.3) = ${rint(-10.3)}");
    println(s"rint(-10.5) = ${rint(-10.5)}");
    println(s"rint(-10.7) = ${rint(-10.7)}"); 
    println(s"rint(5.3) = ${rint(5.3)}"); 
    println(s"rint(5.5) = ${rint(5.5)}");
    println(s"rint(5.7) = ${rint(5.7)}");
    println(s"rint(0.0) = ${rint(0.0)}"); 
    println(s"rint(Double.NaN) = ${rint(Double.NaN)}");
    println("rint(Double.PositiveInfinity) = "
            + rint(Double.PositiveInfinity));
    println("rint(Double.NegativeInfinity) = "
            + rint(Double.NegativeInfinity));
  }
}

The output of the above code will be:

rint(-10.3) = -10.0
rint(-10.5) = -10.0
rint(-10.7) = -11.0
rint(5.3) = 5.0
rint(5.5) = 6.0
rint(5.7) = 6.0
rint(0.0) = 0.0
rint(Double.NaN) = NaN
rint(Double.PositiveInfinity) = Infinity
rint(Double.NegativeInfinity) = -Infinity

❮ Scala - Math Methods