Python Program - Calculate sum of Cubes of Natural numbers

In Mathematics, the natural numbers are all positive numbers which is used for counting like 1, 2, 3, 4, and so on. The smallest natural number is 1.

Objective: Write a Python program which returns sum of cubes of natural numbers starting from 1 to given natural number n, (1³ + 2³ + 3³ + ... + n³).

Method 1: Using while loop

The example below shows how to use while loop to calculate sum of cubes of first n natural numbers.

n = 10
i = 1
sum = 0

#calculating sum of cubes from 1 to n
while(i <= n):
  sum += i**3
  i += 1

print("Sum is:", sum)

The above code will give the following output:

Sum is: 3025

Method 2: Using for loop

The same can be achieved using for loop. Consider the example below:

n = 10
sum = 0

#calculating sum of cubes from 1 to n
for i in range(1, n+1):
  sum += i**3

print("Sum is:", sum)

The above code will give the following output:

Sum is: 3025

Method 3: Using Recursion

Similarly, recursion can be used to calculate the sum.

#recursive function
def Sum(n):
  if(n == 1):
    return 1
  else:
    return (n**3 + Sum(n-1))

print("Sum of Cubes of first 10 natural numbers:", Sum(10))
print("Sum of Cubes of first 20 natural numbers:", Sum(20))

The above code will give the following output:

Sum of Cubes of first 10 natural numbers: 3025
Sum of Cubes of first 20 natural numbers: 44100

Method 4: Using Mathematical Formula

The sum of cubes of first n natural numbers can be mathematically expressed as:

n = 10

#calculating sum of cubes from 1 to n
sum = n*(n+1)/2
sum **= 2

print("Sum is:", sum)

The above code will give the following output:

Sum is: 3025.0