Java - Reverse the Circular Singly Linked List
While working with a circular singly linked list, sometimes it is required to reverse it. Reversing a List produces following result: if the given List is 10->20->30->40->50, after reversing the List the List becomes 50->40->30->20->10.
Reversing a List requires creating three nodes, considering that the list is not empty, which are as follows: tempNode pointing to head, prevNode pointing to head and curNode pointing to next of head. Then make next of prevNode as itself to make the first node as last node of the reversed list. After that, while the curNode is not head adjust links (unlink curNode and link it to the reversed list from front and modify curNode and prevNode to the next element in the list). At last, make the prevNode (last node) as head.
The function reverseList is created for this purpose. It is a 4-step process.
void reverseList() { //1. If head is not null create three nodes // prevNode - pointing to head, // tempNode - pointing to head, // curNode - pointing to next of head if(this.head != null) { Node prevNode = this.head; Node tempNode = this.head; Node curNode = this.head.next; //2. assign next of prevNode as itself to make the // first node as last node of the reversed list prevNode.next = prevNode; while(curNode != this.head) { //3. While the curNode is not head adjust links // (unlink curNode and link it to the reversed list // from front and modify curNode and prevNode) tempNode = curNode.next; curNode.next = prevNode; this.head.next = curNode; prevNode = curNode; curNode = tempNode; } //4. Make prevNode (last node) as head this.head = prevNode; } }
The below is a complete program that uses above discussed concept to reverse a given circular singly linked list.
//node structure class Node { int data; Node next; }; class LinkedList { Node head; LinkedList(){ head = null; } //Add new element at the end of the list void push_back(int newElement) { Node newNode = new Node(); newNode.data = newElement; newNode.next = null; if(head == null) { head = newNode; newNode.next = head; } else { Node temp = new Node(); temp = head; while(temp.next != head) temp = temp.next; temp.next = newNode; newNode.next = head; } } //reverse the list void reverseList() { if(this.head != null) { Node prevNode = this.head; Node tempNode = this.head; Node curNode = this.head.next; prevNode.next = prevNode; while(curNode != this.head) { tempNode = curNode.next; curNode.next = prevNode; this.head.next = curNode; prevNode = curNode; curNode = tempNode; } this.head = prevNode; } } //display the content of the list void PrintList() { Node temp = new Node(); temp = this.head; if(temp != null) { System.out.print("The list contains: "); while(true) { System.out.print(temp.data + " "); temp = temp.next; if(temp == this.head) break; } System.out.println(); } else { System.out.println("The list is empty."); } } }; // test the code public class Implementation { public static void main(String[] args) { LinkedList MyList = new LinkedList(); //Add five elements in the list. MyList.push_back(10); MyList.push_back(20); MyList.push_back(30); MyList.push_back(40); MyList.push_back(50); //Display the content of the list. MyList.PrintList(); //Reversing the list. MyList.reverseList(); //Display the content of the list. MyList.PrintList(); } }
The above code will give the following output:
The list contains: 10 20 30 40 50 The list contains: 50 40 30 20 10