C++ <algorithm> - replace_copy() Function
The C++ algorithm::replace_copy function is used to copy all elements in the range [first, last) to the range starting at result, with all values equal to old_value replaced by new_value.
Syntax
template <class InputIterator, class OutputIterator, class T> OutputIterator replace_copy (InputIterator first, InputIterator last, OutputIterator result, const T& old_value, const T& new_value);
Parameters
first |
Specify initial position of the input iterator. The range used is [first,last). |
last |
Specify final position of the input iterator. The range used is [first,last). |
result |
Specify initial position of the output iterator where the result to be stored. |
old_value |
Specify the value to be replaced. |
new_value |
Specify the value to replaced with. |
Return Value
Returns an iterator pointing to the element that follows the last element replaced in result sequence.
Time Complexity
Linear i.e, Θ(n).
Example:
In the example below, the algorithm::replace_copy function is used to copy all elements of an array to a vector, with all elements equal to 5 replaced by 9.
#include <iostream> #include <algorithm> #include <vector> using namespace std; int main (){ int arr[] = {10, 5, 38, 5, 5, 78}; vector<int> vec(6); vector<int>::iterator it; //copy elements from array to vector and //replace all 5 with 9 in the vector vec replace_copy(arr, arr+6, vec.begin(), 5, 9); cout<<"arr contains:"; for(int i = 0; i < 6; ++i) cout<<" "<<arr[i]; cout<<"\nvec contains:"; for(it = vec.begin(); it != vec.end(); ++it) cout<<" "<<*it; return 0; }
The output of the above code will be:
arr contains: 10 5 38 5 5 78 vec contains: 10 9 38 9 9 78
❮ C++ <algorithm> Library