C++ - Delete the last node of the Circular Doubly Linked List
In this method, the last node of the circular doubly linked list is deleted. For example - if the given list is 10->20->30->40 and the last node is deleted, the list becomes 10->20->30.
Deleting the last node of the Circular Doubly Linked List involves checking the head for empty. If it is not empty and contains only one node then delete the head node. If the list contains more than one node then traverse to the second last node of the list and link it with the head. Finally, delete the last node.
The function pop_back is created for this purpose. It is a 3-step process.
void pop_back() { if(head != NULL) { //1. if head in not null and next of head // is head, release the head if(head->next == head) { head = NULL; } else { //2. Else, traverse to the second last // element of the list Node* temp = head; while(temp->next->next != head) temp = temp->next; //3. Update links of head and second // last node, and delete the last node Node* lastNode = temp->next; temp->next = head; head->prev = temp; free(lastNode); } } }
The below is a complete program that uses above discussed concept of deleting the last node of the circular doubly linked list.
#include <iostream> using namespace std; //node structure struct Node { int data; Node* next; Node* prev; }; class LinkedList { private: Node* head; public: LinkedList(){ head = NULL; } //Add new element at the end of the list void push_back(int newElement) { Node* newNode = new Node(); newNode->data = newElement; newNode->next = NULL; newNode->prev = NULL; if(head == NULL) { head = newNode; newNode->next = head; newNode->prev = head; } else { Node* temp = head; while(temp->next != head) temp = temp->next; temp->next = newNode; newNode->next = head; newNode->prev = temp; head->prev = newNode; } } //Delete last node of the list void pop_back() { if(head != NULL) { if(head->next == head) { head = NULL; } else { Node* temp = head; while(temp->next->next != head) temp = temp->next; Node* lastNode = temp->next; temp->next = head; head->prev = temp; free(lastNode); } } } //display the content of the list void PrintList() { Node* temp = head; if(temp != NULL) { cout<<"The list contains: "; while(true) { cout<<temp->data<<" "; temp = temp->next; if(temp == head) break; } cout<<endl; } else { cout<<"The list is empty.\n"; } } }; // test the code int main() { LinkedList MyList; //Add four elements in the list. MyList.push_back(10); MyList.push_back(20); MyList.push_back(30); MyList.push_back(40); MyList.PrintList(); //Delete the last node MyList.pop_back(); MyList.PrintList(); return 0; }
The above code will give the following output:
The list contains: 10 20 30 40 The list contains: 10 20 30