C - Insert a new node at the start of the Doubly Linked List
In this method, a new node is inserted at the start of the doubly linked list. For example - if the given List is 10->20->30 and a new element 100 is added at the start, the List becomes 100->10->20->30.
Inserting a new node at the start of the doubly linked list is very easy. First, a new node with given element is created. It is then added at the start of the list by linking the head node to the new node.
The function push_front is created for this purpose. It is a 5-step process.
void push_front(struct Node** head_ref, int newElement) { //1. allocate node struct Node *newNode, *temp; newNode = (struct Node*)malloc(sizeof(struct Node)); //2. assign data element newNode->data = newElement; //3. assign null to the next and prev // of the new node newNode->next = NULL; newNode->prev = NULL; //4. Check the list is empty or not, // if empty make the new node as head if(*head_ref == NULL) { *head_ref = newNode; } else { //5. Adjust the links and make the new // node as head (*head_ref)->prev = newNode; newNode->next = *head_ref; *head_ref = newNode; } }
The below is a complete program that uses above discussed concept to insert new node at the start of the doubly linked list.
#include <stdio.h> #include <stdlib.h> //node structure struct Node { int data; struct Node* next; struct Node* prev; }; //Add new element at the start of the list void push_front(struct Node** head_ref, int newElement) { struct Node *newNode, *temp; newNode = (struct Node*)malloc(sizeof(struct Node)); newNode->data = newElement; newNode->next = NULL; newNode->prev = NULL; if(*head_ref == NULL) { *head_ref = newNode; } else { (*head_ref)->prev = newNode; newNode->next = *head_ref; *head_ref = newNode; } } //display the content of the list void PrintList(struct Node* head_ref) { struct Node* temp = head_ref; if(head_ref != NULL) { printf("The list contains: "); while (temp != NULL) { printf("%i ",temp->data); temp = temp->next; } printf("\n"); } else { printf("The list is empty.\n"); } } // test the code int main() { struct Node* MyList = NULL; //Add three elements at the start of the list. push_front(&MyList, 10); push_front(&MyList, 20); push_front(&MyList, 30); PrintList(MyList); return 0; }
The above code will give the following output:
The list contains: 30 20 10