C - Delete last node by key of the Linked List
In this method, last node in the linked list with specified key (value) is deleted. For example - if the given List is 10->20->30->20->40 and the last occurrence of 20 is deleted, the Linked List becomes 10->20->30->40.
If the head of the linked list is not null, create three nodes: 1. lastNode - to track the last node with value equal to key, 2. previousToLast - to track node previous to lastNode, and 3. temp - to traverse through the list. Then traverse the list to its end while updating lastNode and previousToLast whenever find a node with value equal to the specified key. At last delete lastNode and update links accordingly.
The function pop_last is created for this purpose. It is a 3-step process.
void pop_last(struct Node** head_ref, int key) { //1. if head is not null create three nodes // lastNode - to track last node with value // equal to key, previousToLast - to track // node previous to lastNode, temp - to // traverse through the list if(*head_ref != NULL) { struct Node *previousToLast, *lastNode, *temp; previousToLast = NULL; lastNode = NULL; //2. traverse through the list and keep on updating // lastNode and previousToLast whenever find a node // with value equal to the specified key if((*head_ref)->data == key) lastNode = *head_ref; temp = *head_ref; while(temp->next != NULL) { if(temp->next->data == key) { previousToLast = temp; lastNode = temp->next; } temp = temp->next; } //3. Delete the lastNode and update all links if(lastNode != NULL) { if(lastNode == *head_ref) { *head_ref = (*head_ref)->next; free(lastNode); } else { previousToLast->next = lastNode->next; free(lastNode); } } } }
The below is a complete program that uses above discussed concept to delete last occurrence of the specified key (if exists) of the linked list.
#include <stdio.h> #include <stdlib.h> //node structure struct Node { int data; struct Node* next; }; //Add new element at the end of the list void push_back(struct Node** head_ref, int newElement) { struct Node *newNode, *temp; newNode = (struct Node*)malloc(sizeof(struct Node)); newNode->data = newElement; newNode->next = NULL; if(*head_ref == NULL) { *head_ref = newNode; } else { temp = *head_ref; while(temp->next != NULL) { temp = temp->next; } temp->next = newNode; } } //Delete last node by key void pop_last(struct Node** head_ref, int key) { if(*head_ref != NULL) { struct Node *previousToLast, *lastNode, *temp; previousToLast = NULL; lastNode = NULL; if((*head_ref)->data == key) lastNode = *head_ref; temp = *head_ref; while(temp->next != NULL) { if(temp->next->data == key) { previousToLast = temp; lastNode = temp->next; } temp = temp->next; } if(lastNode != NULL) { if(lastNode == *head_ref) { *head_ref = (*head_ref)->next; free(lastNode); } else { previousToLast->next = lastNode->next; free(lastNode); } } } } //display the content of the list void PrintList(struct Node* head_ref) { struct Node* temp = head_ref; if(head_ref != NULL) { printf("The list contains: "); while (temp != NULL) { printf("%i ",temp->data); temp = temp->next; } printf("\n"); } else { printf("The list is empty.\n"); } } // test the code int main() { struct Node* MyList = NULL; //Add five elements at the end of the list. push_back(&MyList, 10); push_back(&MyList, 20); push_back(&MyList, 30); push_back(&MyList, 20); push_back(&MyList, 40); PrintList(MyList); //Delete last occurrence of 20 pop_last(&MyList, 20); PrintList(MyList); return 0; }
The above code will give the following output:
The list contains: 10 20 30 20 40 The list contains: 10 20 30 40