SQLite AS Keyword
The SQLite AS keyword is used in a ALIAS statement and it is used to provide a temporary name to a column of a table, aggregate function column or a table itself. A alias name exists for only for the duration of the query. It facilitates easy to understand names and hence increases readability of a query.
Syntax
The syntax for using SQLite AS keyword in SQLite is given below:
/* Using ALIAS with a column of a table */ SELECT column_name AS alias_name FROM table_name; /* Using ALIAS with an aggregate function */ SELECT SUM(column_name) AS alias_name FROM table_name WHERE condition(s); /* Using ALIAS with a table */ SELECT alias_name_1.column1, alias_name_2.column1, ... FROM table1 AS alias_name_1 INNER JOIN table2 AS alias_name_2 ON alias_name_1.matching_column = alias_name_2.matching_column;
Example:
Consider a database containing tables called Employee and Contact_Info with the following records:
Table 1: Employee table
EmpID | Name | City | Age | Salary |
---|---|---|---|---|
1 | John | London | 25 | 3000 |
2 | Marry | New York | 24 | 2750 |
3 | Jo | Paris | 27 | 2800 |
4 | Kim | Amsterdam | 30 | 3100 |
5 | Ramesh | New Delhi | 28 | 3000 |
6 | Huang | Beijing | 28 | 2800 |
Table 2: Contact_Info table
Phone_Number | EmpID | Address | Gender |
---|---|---|---|
+1-8054098000 | 2 | Brooklyn, New York, USA | F |
+33-147996101 | 3 | Grenelle, Paris, France | M |
+31-201150319 | 4 | Geuzenveld, Amsterdam, Netherlands | F |
+86-1099732458 | 6 | Yizhuangzhen, Beijing, China | M |
+65-67234824 | 7 | Yishun, Singapore | M |
+81-357799072 | 8 | Koto City, Tokyo, Japan | M |
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ALIAS with a column: The below statement is used to create a aliases of columns - name and City of the Employee table.
SELECT Name AS [Employee Name], Age AS [Employee Age], City FROM Employee;
This will produce the result as shown below:
Employee Name Employee Age City John 25 London Marry 24 New York Jo 27 Paris Kim 30 Amsterdam Ramesh 28 New Delhi Huang 28 Beijing -
ALIAS with an aggregate function: The below query is used to fetch the number of employees whose age is greater than 27.
SELECT COUNT(Name) AS [Number of Employees] FROM Employee WHERE Age > 27;
This will bring the following result:
Number of Employees 3 -
ALIAS with a table: To inner join Employee and Contact_Info tables based on matching column EmpID, the statement is given below. While performing inner join of two tables, aliases of tables are used.
SELECT A.Name, A.Age, B.Address FROM Employee AS A INNER JOIN Contact_Info AS B ON A.EmpID = B.EmpID;
The result of above query will be:
Name Age Address Marry 24 Brooklyn, New York, USA Jo 27 Grenelle, Paris, France Kim 30 Geuzenveld, Amsterdam, Netherlands Huang 28 Yizhuangzhen, Beijing, China
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