Rust - Bitwise OR operator
The Bitwise OR operator (|) is a binary operator which takes two bit patterns of equal length and performs the logical OR operation on each pair of corresponding bits. It returns 1 if either or both bits at the same position are 1, else returns 0.
Bit_1 | Bit_2 | Bit_1 | Bit_2 |
---|---|---|
0 | 0 | 0 |
1 | 0 | 1 |
0 | 1 | 1 |
1 | 1 | 1 |
The example below describes how bitwise OR operator works:
50 | 25 returns 59 50 -> 110010 (In Binary) | 25 -> | 011001 (In Binary) ---- -------- 59 <- 111011 (In Binary)
The code of using Bitwise OR operator (|) is given below:
fn main() { let x = 50; let y = 25; //Bitwise OR operation let z = x | y; //Displaying the result println!("z = {}", z); }
The output of the above code will be:
z = 59
Example: Find largest power of 2 less than or equal to given number
Consider an integer 1000. In the bit-wise format, it can be written as 1111101000. However, all bits are not written here. A complete representation will be 32 bit representation as given below:
00000000000000000000001111101000
Performing
00000000000000000000001111111111
Adding one to this result and then right shifting the result by one place will give largest power of 2 less than or equal to 1000.
00000000000000000000001000000000
The below code will calculate the largest power of 2 less than or equal to given number.
fn max_power_of_two(n: i32) -> i32{ let mut n = n; //changing all right side bits to 1. n = n | (n>>1); n = n | (n>>2); n = n | (n>>4); n = n | (n>>8); n = n | (n>>16); //adding 1 to n makes smallest power //of 2 greater than given number n = n + 1; //right shift by one position makes //largest power of 2 less than or //equal to given number n = n >> 1; return n; } fn main() { println!("max_power_of_two(100) = {}", max_power_of_two(100)); println!("max_power_of_two(500) = {}", max_power_of_two(500)); println!("max_power_of_two(1000) = {}", max_power_of_two(1000)); }
The above code will give the following output:
max_power_of_two(100) = 64 max_power_of_two(500) = 256 max_power_of_two(1000) = 512
❮ Rust - Operators