PHP $argc Variable
The PHP $argc variable contains the number of arguments passed to the current script when running from the command line.
Note: The script's filename is always passed as an argument to the script, therefore the minimum value of $argc is 1.
Note: This variable is not available when register_argc_argv in php.ini is disabled.
Example: $argc example
The example below demonstrates the usage of $argc variable.
<?php var_dump($argc); ?>
When executing the above example with: php script.php arg1 arg2 arg3 arg4
The output of the above script will be similar to:
int(5)
Example: adding multiple arguments
Consider one more example where this variable is used to add multiple number of arguments.
<?php $n = $argc; $result = 0; for($i = 1; $i < $n; $i++) $result = $result + $argv[$i]; echo "Addition = ". $result; ?>
When executing the above example with: php script.php 10 20 30
The output of the above script will be similar to:
Addition = 60
Note: This variable is also available as $_SERVER['argc'].
❮ PHP - Predefined Variables