Java Random - nextLong() Method
The java.util.Random.nextLong() method returns the next pseudorandom, uniformly distributed long value from this random number generator's sequence.
Syntax
public long nextLong()
Parameters
No parameter is required.
Return Value
Returns the next pseudorandom, uniformly distributed long value from this random number generator's sequence.
Exception
NA
Example:
In the example below, the java.util.Random.nextLong() method is used to get pseudorandom number, uniformly distributed long value.
import java.util.*;
public class MyClass {
public static void main(String[] args) {
//creating a random object
Random rand = new Random();
//printing uniformly distributed long random numbers
for(int i = 0; i < 5; i++)
System.out.println("Next Long Value: " + rand.nextLong());
}
}
One of the possible outcome is given below:
Next Long Value: 4825829200540759552 Next Long Value: -9066867453086882798 Next Long Value: 8469836022359840602 Next Long Value: -4746186347640095910 Next Long Value: 3109369539146836557
❮ Java.util - Random
