Java Random - ints() Method
The java.util.Random.ints() method returns an effectively unlimited stream of pseudorandom int values, each conforming to the given origin (inclusive) and bound (exclusive).
Syntax
public IntStream ints(int randomNumberOrigin, int randomNumberBound)
Parameters
randomNumberOrigin |
Specify the origin (inclusive) of each random value. |
randomNumberBound |
Specify the bound (exclusive) of each random value. |
Return Value
Returns a stream of pseudorandom int values, each with the given origin (inclusive) and bound (exclusive).
Exception
Throws IllegalArgumentException, if randomNumberOrigin is greater than or equal to randomNumberBound.
Example:
In the example below, the java.util.Random.ints() method is used to get a stream of pseudorandom int values in the given range.
import java.util.*; import java.util.stream.IntStream; public class MyClass { public static void main(String[] args) { //creating a random object Random rand = new Random(); //generating a stream containing int random //numbers between 500(inclusive) and 1000(exclusive) IntStream stream = rand.ints(500, 1000); //printing 10 random numbers from the stream stream.limit(10).forEach(System.out::println); } }
One of the possible outcome is given below:
995 965 775 829 747 510 658 601 952 905
❮ Java.util - Random