Java Long - parseLong() Method
The java.lang.Long.parseLong() method is used to parse the string argument as a signed decimal long. The characters in the string must all be decimal digits, except that the first character may be an ASCII minus sign '-' (\u002D') to indicate a negative value or an ASCII plus sign '+' ('\u002B') to indicate a positive value. The resulting long value is returned, exactly as if the argument and the radix 10 were given as arguments to the parseLong(java.lang.String, int) method.
Syntax
public static long parseLong(String s) throws NumberFormatException
Parameters
s |
Specify a String containing the long representation to be parsed. |
Return Value
Returns the long represented by the argument in decimal.
Exception
Throws NumberFormatException, if the string does not contain a parsable long.
Example:
In the example below, the java.lang.Long.parseLong() method is used to parse the string argument as a signed decimal long.
import java.lang.*; public class MyClass { public static void main(String[] args) { //creating a string holding long value String x = "25"; //creating long value long y = Long.parseLong(x); //printing the string System.out.println("The string is: " + x); //printing the long value System.out.println("The long value is: " + y); } }
The output of the above code will be:
The string is: 25 The long value is: 25
❮ Java.lang - Long