Java Long - numberOfTrailingZeros() Method

The java.lang.Long.numberOfTrailingZeros() method returns the number of zero bits following the lowest-order ("rightmost") one-bit in the two's complement binary representation of the specified long value. The method returns 64 if the specified value has no one-bits in its two's complement representation, in other words if it is equal to zero.

Syntax

public static int numberOfTrailingZeros(long i)

Parameters

Return Value

Returns the number of zero bits following the lowest-order ("rightmost") one-bit in the two's complement binary representation of the specified long value, or 64 if the value is equal to zero.

Exception

NA.

Example:

In the example below, the java.lang.Long.numberOfTrailingZeros() method returns the number of zero bits following the rightmost one-bit in the two's complement binary representation of the given long value.

import java.lang.*;

public class MyClass {
  public static void main(String[] args) {
    
    //creating a long value
    long x = 50; 

    //printing value of x, its binary 
    //representation and numberOfTrailingZeros
    System.out.println("The values of x is: " + x);
    System.out.print("The binary representation of x is: ");
    System.out.println(Long.toBinaryString(x));
    System.out.print("The numberOfTrailingZeros is: ");
    System.out.println(Long.numberOfTrailingZeros(x));
  }
}

The output of the above code will be:

The values of x is: 50
The binary representation of x is: 110010
The numberOfTrailingZeros is: 1