Java Double - doubleToRawLongBits() Method
The java.lang.Double.doubleToRawLongBits() method returns a representation of the specified floating-point value according to the IEEE 754 floating-point "double format" bit layout, preserving Not-a-Number (NaN) values. It includes the following important points:
- If the argument is positive infinity, the result is 0x7ff0000000000000L.
- If the argument is negative infinity, the result is 0xfff0000000000000L.
- If the argument is NaN, the result is the long integer representing the actual NaN value. Unlike the doubleToLongBits method, doubleToRawLongBits does not collapse all the bit patterns encoding a NaN to a single "canonical" NaN value.
Syntax
public static long doubleToRawLongBits(double value)
Parameters
value |
Specify a double precision floating-point number. |
Return Value
Returns the bits that represent the floating-point number.
Exception
NA.
Example:
In the example below, the java.lang.Double.doubleToRawLongBits() method returns the bits that represent the given floating-point number.
import java.lang.*; public class MyClass { public static void main(String[] args) { //creating double values double x = 25; double y = -25; //printing the bit which represents x System.out.print("doubleToRawLongBits value of x is: "); System.out.println(Double.doubleToRawLongBits(x)); //printing the bit which represents y System.out.print("doubleToRawLongBits value of y is: "); System.out.println(Double.doubleToRawLongBits(y)); } }
The output of the above code will be:
doubleToRawLongBits value of x is: 4627730092099895296 doubleToRawLongBits value of y is: -4595641944754880512
❮ Java.lang - Double