Java Byte - valueOf() Method
The java.lang.Byte.valueOf() method returns a Byte object holding the value given by the specified String. The argument is interpreted as representing a signed decimal byte, exactly as if the argument were given to the parseByte(java.lang.String) method. The result is a Byte object that represents the byte value specified by the string.
In other words, this method returns a Byte object equal to the value of: new Byte(Byte.parseByte(s)).
Syntax
public static Byte valueOf(String s) throws NumberFormatException
Parameters
s |
Specify the string to be parsed. |
Return Value
Returns a Byte object holding the value represented by the string argument.
Exception
Throws NumberFormatException, if the String does not contain a parsable byte.
Example:
In the example below, the java.lang.Byte.valueOf() method returns a Byte object holding the value given by the specified String.
import java.lang.*; public class MyClass { public static void main(String[] args) { //creating a string holding byte value String x = "25"; //creating Byte object Byte y = Byte.valueOf(x); //printing the string System.out.println("The string is: " + x); //printing the Byte object System.out.println("The Byte object is: " + y); } }
The output of the above code will be:
The string is: 25 The Byte object is: 25
❮ Java.lang - Byte