Java BitSet - valueOf() Method
The java.util.BitSet.valueOf() method returns a new bit set containing all the bits in the given long array.
More precisely,
BitSet.valueOf(longs).get(n) == ((longs[n/64] & (1<<(n%64))) != 0) for all n < 64 * longs.length
Syntax
public static BitSet valueOf(long[] longs)
Parameters
longs |
Specify a long array containing sequence of bits to be used as the initial bits of the new bit set. |
Return Value
Returns a BitSet containing all the bits in the long array.
Exception
NA.
Example:
In the example below, the java.util.BitSet.valueOf() method returns a BitSet which contains all the bits in the specified long array.
import java.util.*; public class MyClass { public static void main(String[] args) { //creating a long array long Arr[] = {10, 5, 25}; //creating bit set from given long array BitSet BSet = new BitSet(); BSet = BitSet.valueOf(Arr); //printing BitSet System.out.println("BSet contains: " + BSet); } }
The output of the above code will be:
BSet contains: {1, 3, 64, 66, 128, 131, 132}
❮ Java.util - BitSet