Java ArrayList - sort() Method
The java.util.ArrayList.sort() method is used to sort the elements of the list according to the order induced by the specified comparator.
Syntax
public void sort(Comparator<? super E> c)
Here, E is the type of element maintained by the container.
Parameters
c |
Specify the comparator used to compare list elements. If null, element's natural ordering is used. |
Return Value
void type.
Exception
NA.
Example:
In the example below, the java.util.ArrayList.sort() method is used to sort the given list.
import java.util.*; public class MyClass { public static void main(String[] args) { //creating an ArrayList ArrayList<Integer> MyList = new ArrayList<Integer>(); //populating the ArrayList MyList.add(50); MyList.add(40); MyList.add(10); MyList.add(30); MyList.add(20); //printing the ArrayList System.out.println("MyList contains: "+ MyList); //sorting the ArrayList Collections.sort(MyList); //printing the ArrayList System.out.println("MyList contains: "+ MyList); } }
The output of the above code will be:
MyList contains: [50, 40, 10, 30, 20] MyList contains: [10, 20, 30, 40, 50]
❮ Java.util - ArrayList