C <math.h> - isfinite()
The C <math.h> isfinite() macro returns true if the given argument is a finite value, else returns false. A finite value is any floating-point value that is neither infinity nor NaN (Not-A-Number).
Syntax
isfinite(x)
Parameters
x |
Specify a floating-point value. |
Return Value
Returns true (non-zero value) if the argument is an infinity value, else returns false (zero value).
Example:
The example below shows the usage of isfinite() macro.
#include <stdio.h>
#include <math.h>
int main (){
printf("isfinite(10.5): %d\n", isfinite(10.5));
printf("isfinite(1.0/0.0): %d\n", isfinite(1.0/0.0));
printf("isfinite(0.0/0.0): %d\n", isfinite(0.0/0.0));
printf("isfinite(sqrt(-1.0)): %d\n", isfinite(sqrt(-1.0)));
return 0;
}
The output of the above code will be:
isfinite(10.5): 1 isfinite(1.0/0.0): 0 isfinite(0.0/0.0): 0 isfinite(sqrt(-1.0)): 0
❮ C <math.h> Library
