Java Integer - compare() Method
The java.lang.Integer.compare() method is used to compare two int values numerically. The value returned is identical to what would be returned by: Integer.valueOf(x).compareTo(Integer.valueOf(y)).
Syntax
public static int compare(int x, int y)
Parameters
x |
Specify the first int to compare. |
y |
Specify the second int to compare. |
Return Value
Returns the value 0 if x == y; a value less than 0 if x < y; and a value greater than 0 if x > y.
Exception
NA.
Example:
In the example below, the java.lang.Integer.compare() method is used to compare given int values.
import java.lang.*; public class MyClass { public static void main(String[] args) { //creating int values int val1 = 5; int val2 = 5; int val3 = -5; //comparing int values System.out.println("comparing val1 and val2: " + Integer.compare(val1, val2)); System.out.println("comparing val1 and val3: " + Integer.compare(val1, val3)); System.out.println("comparing val3 and val1: " + Integer.compare(val3, val1)); } }
The output of the above code will be:
comparing val1 and val2: 0 comparing val1 and val3: 1 comparing val3 and val1: -1
❮ Java.lang - Integer